Genzod Posted September 1, 2009 Report Share Posted September 1, 2009 (edited) I tried splitting the difference between Haflinger and Slayer... (-66.51326044311185,-53.4375) gives 72% efficiency. Edited September 2, 2009 by GenZod Quote Link to comment Share on other sites More sharing options...
AirMe Posted September 2, 2009 Author Report Share Posted September 2, 2009 When we find it, please post a screen shot. Quote Link to comment Share on other sites More sharing options...
suryanto tan Posted September 2, 2009 Report Share Posted September 2, 2009 (edited) marker2 = new GMarker(new GLatLng(-83.44032649527307,-99.140625),{icon:iconType,draggable: false}); marker3 = new GMarker(new GLatLng(-83.4803661137381,-113.5986328125),{icon:iconType,draggable: false}); Gives 80%. As it is difficult to determine the longitude and latitude simultaneously, the next player might want to try the same latitude, and change the longitude only. Latitude: the same as before. -83.44032649527307 Longitude: some where to the left, perhaps -170.000 something. Edited September 2, 2009 by suryanto tan Quote Link to comment Share on other sites More sharing options...
blaster45 Posted September 3, 2009 Report Share Posted September 3, 2009 (edited) This moon location just got me 90% marker3 = new GMarker(new GLatLng(-55.07836723201513,77.87109375),{icon:iconType,draggable: false}); I got 88% with this Moon location, marker2 = new GMarker(new GLatLng(-51.17934297928927,77.34375),{icon:iconType,draggable: false}); Edited September 3, 2009 by Big Richard Quote Link to comment Share on other sites More sharing options...
Steelrat Posted September 3, 2009 Report Share Posted September 3, 2009 This moon location just got me 90% marker3 = new GMarker(new GLatLng(-55.07836723201513,77.87109375),{icon:iconType,draggable: false}); I got 88% with this Moon location, marker2 = new GMarker(new GLatLng(-51.17934297928927,77.34375),{icon:iconType,draggable: false}); These coord sets with the claimed efficiencies seem way off, i have no idea. Quote Link to comment Share on other sites More sharing options...
angryraccoon Posted September 3, 2009 Report Share Posted September 3, 2009 -133.59375 by -83.9792594988 80% Quote Link to comment Share on other sites More sharing options...
theArrowheadian Posted September 3, 2009 Report Share Posted September 3, 2009 (edited) Got me 85% Edit: I went a little too far east for what i wanted. Edited September 3, 2009 by theArrowheadian Quote Link to comment Share on other sites More sharing options...
AirMe Posted September 3, 2009 Author Report Share Posted September 3, 2009 Got me 85% Edit: I went a little too far east for what i wanted. I got 89% just west of you. Quote Link to comment Share on other sites More sharing options...
Danielg42 Posted September 3, 2009 Report Share Posted September 3, 2009 (edited) Got 91% by going a bit south of the circle a few posts back. -56.07836723201513,77.87109375 is what I was shooting for, how do I tell my exact lat / longitude from the CN view? http://www.cybernations.net/national_wonde...p;Location=Moon Edited September 3, 2009 by Danielg42 Quote Link to comment Share on other sites More sharing options...
Bodvar Jarl Posted September 3, 2009 Report Share Posted September 3, 2009 http://www.cybernations.net/national_wonde...p;Location=Moon 84% -45.08903556483102,73.65234375 Quote Link to comment Share on other sites More sharing options...
Earth Shaker Posted September 3, 2009 Report Share Posted September 3, 2009 Got 91% by going a bit south of the circle a few posts back.-56.07836723201513,77.87109375 is what I was shooting for, how do I tell my exact lat / longitude from the CN view? http://www.cybernations.net/national_wonde...p;Location=Moon This post shows how to exactly find your coordinates : Post No.59 Quote Link to comment Share on other sites More sharing options...
JoshuaR Posted September 3, 2009 Report Share Posted September 3, 2009 These coord sets with the claimed efficiencies seem way off, i have no idea. Mm, thanks for the graph. Do they really seem so far off? The hotspot is closer to the south pole than usual, so everything in the south will be fairly close. The entire bottom line of the graph will fold in on itself. As far as calculations go, does anyone have the best clue how to triangulate? Anyone have a guess as to how to triangulate?I was thinking this, below, but it's got the following problems... (x1-xr)^2+(y1-yr)^2=(AR)^2 (x2-xr)^2+(y2-yr)^2=(BR)^2 (x3-xr)^2+(y3-yr)^2=(CR)^2 Where x1 is the x coordinate, y1 is the y coordinate of base 1. xr and yr are the actual coordinates of the hot spot. R is the radius of the hotspot's influence, or something... A, B, C are just the efficiency modifiers, so like 76% efficiency is = (0.76R)^2 Since 50% is zero, we might also be looking at A = (efficiency - 50) * 2. So that might also be tried. 76% would really be 52% if the scale goes from 50-100. More likely, the whole thing is wrong since A, B, and C are non linear anyway (the efficiencies), and we need another formula for determining those. That, and the problem of the coordinates being on a sphere. This above formula is assuming a flat map. If all the bases are in a line of latitude at 80% and at completely random longitudes, for example, they could all be equidistant to the hotspot if it's on the north or south poles. So there's trilateration: http://en.wikipedia.org/wiki/Trilateration And there, the problem of having three equations for 4 unknowns: x, y, z, and R. At least this is how I see it right now... Please offer suggestions , especially if I missed something stupid and obvious. Quote Link to comment Share on other sites More sharing options...
Danielg42 Posted September 3, 2009 Report Share Posted September 3, 2009 (edited) This post shows how to exactly find your coordinates :Post No.59 Thanks! -56.704505614169356, 77.783203125 are my exact coordinates and I'm at 91% Ok I did some drawing of my own, plotting out my point along with some of the others. Maybe someone can try -60.4, 77.5 At worst you get close to 90. Here's my sketch, sorry for the blurryness, phone camera. Based on the 3 points I had, it seemed that as you get closer to the spot the area decreased by 25ish percent per efficiency percentage, so I used that to guesstimate. Edited September 4, 2009 by Danielg42 Quote Link to comment Share on other sites More sharing options...
john_268 Posted September 4, 2009 Report Share Posted September 4, 2009 (edited) Unfortunatly when i was going to look at the current lat and long i sneezed and hit the left mouse button rather then the right. Oh Well anyway i got 85% in this spot towards the bottom. Hope that it helps out with the search for this month's holy grail!! GLatLng(-81.09321385260837,146.953125 Edited September 4, 2009 by john_268 Quote Link to comment Share on other sites More sharing options...
Overlord Shinnra Posted September 5, 2009 Report Share Posted September 5, 2009 (-75.14077784070427,80.15625) Got me 94%. - Moon Colony (-80.17871349622823,82.78125) Got me 91%. - Moon Base Screen Shot Below (the colony is the one on top) Quote Link to comment Share on other sites More sharing options...
RoadRash Posted September 5, 2009 Report Share Posted September 5, 2009 (edited) moon base(-80.17871349622823,82.78125)Got me 91%. - Moon Base this got me 91% didnt change my collection but lowered my bills by 90k Edited September 5, 2009 by greco Quote Link to comment Share on other sites More sharing options...
Golan 1st Posted September 5, 2009 Report Share Posted September 5, 2009 I translated the locations above to 3D and calculated the distances on the surface of the moon. Assuming that efficiency depends linearly on the distance from the hot spot (which fits well with the information of coordinates and efficiency above, with little error tolerance), I expect to find the hot spot in the area of (-81.354, 77.00565). Quote Link to comment Share on other sites More sharing options...
TheyCallMeJeezy Posted September 6, 2009 Report Share Posted September 6, 2009 is the hotspot in the same location for all lunar wonders? Quote Link to comment Share on other sites More sharing options...
admin Posted September 6, 2009 Report Share Posted September 6, 2009 I've added a location indicator on the popup boxes for the Moon & Mars wonders so that you don't have to go digging through the source code to get your coordinates. Hope that helps. Quote Link to comment Share on other sites More sharing options...
thedestro Posted September 6, 2009 Report Share Posted September 6, 2009 I've added a location indicator on the popup boxes for the Moon & Mars wonders so that you don't have to go digging through the source code to get your coordinates. Hope that helps. What did I say a few weeks ago? Quote Link to comment Share on other sites More sharing options...
Golan 1st Posted September 6, 2009 Report Share Posted September 6, 2009 My prediction for the hot spot gives 90% only :/ Quote Link to comment Share on other sites More sharing options...
RoadRash Posted September 6, 2009 Report Share Posted September 6, 2009 I've added a location indicator on the popup boxes for the Moon & Mars wonders so that you don't have to go digging through the source code to get your coordinates. Hope that helps. thank you sir Quote Link to comment Share on other sites More sharing options...
Overlord Shinnra Posted September 6, 2009 Report Share Posted September 6, 2009 I translated the locations above to 3D and calculated the distances on the surface of the moon. Assuming that efficiency depends linearly on the distance from the hot spot (which fits well with the information of coordinates and efficiency above, with little error tolerance), I expect to find the hot spot in the area of (-81.354, 77.00565). my guess is the equation for the location of the hotspot is exponential. Not linear. Quote Link to comment Share on other sites More sharing options...
JoshuaR Posted September 7, 2009 Report Share Posted September 7, 2009 Golan 1st, did you say you calculated the distances to the hotspot traveling on the shortest path on the Surface of the moon, or were you traveling through the center of the moon? Quote Link to comment Share on other sites More sharing options...
Golan 1st Posted September 7, 2009 Report Share Posted September 7, 2009 Golan 1st, did you say you calculated the distances to the hotspot traveling on the shortest path on the Surface of the moon, or were you traveling through the center of the moon? shortest path on the Surface of the moon Well, to be accurate, I checked angles between the lines connecting the center of the moon to these locations, which are proportional to the shortest distance on the surface of the moon. Shinnra, is your guess based on some data? Quote Link to comment Share on other sites More sharing options...
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